Tuesday, May 26, 2020

Life, Death, and Research Paper Writing Service Cheap

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Friday, May 15, 2020

Ways to Control Greenhouse Effects - Free Essay Example

Sample details Pages: 1 Words: 357 Downloads: 9 Date added: 2017/09/11 Category Advertising Essay Did you like this example? The greenhouse effect is an effect on the atmosphere as a result of the presence of a certain gases called greenhouse gases which are made up of carbon dioxide, chlorofluorocarbons, methane, nitrous oxide, low-level ozone and water vapour. Greenhouse gases in the atmosphere are similar to the greenhouse glass panes which trap the heat and warm the greenhouse. When the greenhouse effect occurs, sunlight enters the Earth’s atmosphere and while some solar radiation is reflected back to space, most of the radiation is absorbed by the Earth. As the Earth is warmed, heat in the form of infrared radiation is radiated back into the space. However, much of this does not escape from the atmosphere but remains trapped by the greenhouse gases, warming the atmosphere and cause the infrared rays to be radiated back towards the surface of the Earth. The causes of greenhouse effect include deforestation. Our population is increasing and to accommodate to needs for amenities and economic stability, more and more forests are being cut down or burnt. Don’t waste time! Our writers will create an original "Ways to Control Greenhouse Effects" essay for you Create order This in turn heightens the percentage of carbon dioxide as there are not enough plants to absorb carbon dioxide for photosynthesis. To overcome this problem, the authority has to implement regulations to address this issue by constraining the law and penalising those who do not comply with the law. Besides, the burning of fossil fuels like petroleum has greatly raised the levels of carbon dioxide. For this, alternative sources of energy such as geothermal energy, biomass energy and wind energy should be utilised so that the environment is not affected by this combustion activity. Moreover, electrical appliances are a contributor to this issue too. Electrical appliances like refrigerator and air conditioner releases chlorofluorocarbons which have added to the greenhouse effects. Therefore, hydrofluorocarbons (HCFs) should substitute CFCs as these gases break down in the atmosphere and return to the Earth in the form of rain water and hence are more environmentally-friendly. Conclusively, scientists should conduct more researches on ways to address this crisis. Hopefully, in the years to come, we would have gained back all the richness of the nature that we seem to have lost.

Wednesday, May 6, 2020

Essay on Oral Dracula From A Reader And Femminist...

Bram Stokers â€Å"Dracula† an oral presentation Good Morning/Afternoon Today I will review Bram stokers’ 1897 novel Dracula, the approaches I will be using to reviewing the novel include the world centred approach, and the reader response approach exploring the themes of reader positioning and the authors intented reading and reader, then focusing on the world centred approach of the feministtheory. reader centred -attention on the reader -different readers from different social, cultural, religious backgrounds ect, will being and interpret different meaning to text, reflecting from there own backgrounds and life experiences -perception of real life and the way the text presents personal or human life experiences world centred approach†¦show more content†¦Mina Murray is Jonathans’ fiancee and later into the novel they wed, Mina is the heroine she is presented as a practical woman, working as a school teacher, the reader may relate to her personally through personal experience. Mina during the novel is victimised by dracula, Mina represents to the reader purity, innocence and religious faith .Slowly the relationships between the characters become evident we find Minas’ bestfriend Miss Lucy Westenra, Is the counts first victim. Lucy is portaryed as an attractive, flirtatious woman, who is the interest of three young men who are also so of the character there is John Seward a young doctor, and the administrator of an asylum located near draculas English home. Arthur Holmwood a man of wealth, Who becomes Lucy’s’ fiancee and a close friend to her other suitors, Then her final suitorShow MoreRelatedOral Dracula from a Reader and Femminist Perspective1443 Words   |  6 PagesBram Stokers Dracula an oral presentation Good Morning/Afternoon Today I will review Bram stokers 1897 novel Dracula, the approaches I will be using to reviewing the novel include the world centred approach, and the reader response approach exploring the themes of reader positioning and the authors intented reading and reader, then focusing on the world centred approach of the feministtheory. reader centred -attention on the reader -different readers from different social, cultural, religious

Tuesday, May 5, 2020

Physics Problem Essay Example For Students

Physics Problem Essay A man is able to row a boat at 3 MPH in still water. If he rows his boat pointed straight across a river with a current of 4 MPH, what is his net velocity? If the river is 0. 5 miles wide, at what point will he land on the other side? Solution: The first step in problem solving is to identify the problem type. In this problem we are asked for a net velocity. Since velocities behave as vectors, then we have a vector addition problem. A figure is drawn with the vectors indicated. Here iv is the boats velocity still water), IVR is the rivers velocity, and event is the resultant (net) of these two velocities. The vector equation pertinent to the problem is: event = iv O IVR . iv IVR v net A coordinate system is selected as shown. Note that all vector problems are calculated by means of the component method (rectangular resolution), and hence a specified coordinate system is essential. Since our vector space is 2-dimensional, the vector equation above reduces to two scalar equations. One for each of the necessary components. We calculate the components of the vectors to be added. For the coordinate system selected we have: event x = VBG + IVR = 3 + 3 MPH ; event y = by + vary = O + 4 = 4 MPH The answer for the net velocity can be specified in two equivalent ways. One way is to specify the two components for the net velocity (as done above). The second method is to state the magnitude and direction for event. Eleven = 3+42=25 = 5 MPH. The direction is given by an angle. From the figure we see we have a 3,4,5 right triangle. Hence, we can determine B by any of the following: sin B = ivy/event = 4/5 coos B = event = 3/5 tan B = = 4/3 = 530 = 530 = 530 3 4 1-2 The problem also asks at what point he will reach the other side of the river. Since all velocities in the problem are constant we may use: speed x time = distance. Thus the time to cross the river = 0. 5/3 = 1/6 = . 166 hrs = 10 min. Distance traveled downstream = = 2/3 mile. Total distance traveled = = 5/6 mile. He will arrive at a point on the other bank 2/3 off mile below his starting point. 2) A boy walks 4 km west, 2 km south, and then 1 km east. Determine the total distance he walked and his net displacement. If it took him 1. 2 hours to complete the walk, find his average speed and his average velocity. Solution: We are dealing with distances (scalar), displacements (vector), speeds (scalar), and Velocities (vectors). Hence we have both scalar addition and vector addition problems. We draw a figure indicating the 3 displacement vectors. Del B Dent DES We select a coordinate system (W S). The total distance walked is simply 7 km (scalar addition). Since he covered this distance in 1. Hours, then his walking speed was: 7/1. 2 = 5. 83 km/hrs. Displacement is a vector quantity. Hence: Dent = Del DO 0 DO . The calculation is performed by adding the components of each vector. Thus: Dent W = DID + + DEW = 4+0- 1 = 3 km; Dent S = DISC + DES + DBS = O + 2 2 km. Note that the West component of displacement DO is negative since the direction is east. The magnitude and direction can be determined from the resultant components. I Deten t = 32+22 13 = 3. 61 km. B = 33. 70. In words, the total The direction can be found from any of the trig functions. Tan B = DES/DO = 2/3 By definition, the average velocity is given by Arm where Ar is the total (net) displacement. Hence, eave = 3. 61/1. 2 = 3. 01 km/hrs at 33. 70 south of west. Note that the magnitude of the average velocity is not the same as the Walking speed. This illustrates the directional aspect of velocity. Suppose you walked for two hours and ended up back at your starting position. Your net displacement would be O, and your average velocity is also O. Note also the relationship between position and displacement. .u436c1e03cd48d98dd0fcd00e59862316 , .u436c1e03cd48d98dd0fcd00e59862316 .postImageUrl , .u436c1e03cd48d98dd0fcd00e59862316 .centered-text-area { min-height: 80px; position: relative; } .u436c1e03cd48d98dd0fcd00e59862316 , .u436c1e03cd48d98dd0fcd00e59862316:hover , .u436c1e03cd48d98dd0fcd00e59862316:visited , .u436c1e03cd48d98dd0fcd00e59862316:active { border:0!important; } .u436c1e03cd48d98dd0fcd00e59862316 .clearfix:after { content: ""; display: table; clear: both; } .u436c1e03cd48d98dd0fcd00e59862316 { display: block; transition: background-color 250ms; webkit-transition: background-color 250ms; width: 100%; opacity: 1; transition: opacity 250ms; webkit-transition: opacity 250ms; background-color: #95A5A6; } .u436c1e03cd48d98dd0fcd00e59862316:active , .u436c1e03cd48d98dd0fcd00e59862316:hover { opacity: 1; transition: opacity 250ms; webkit-transition: opacity 250ms; background-color: #2C3E50; } .u436c1e03cd48d98dd0fcd00e59862316 .centered-text-area { width: 100%; position: relative ; } .u436c1e03cd48d98dd0fcd00e59862316 .ctaText { border-bottom: 0 solid #fff; color: #2980B9; font-size: 16px; font-weight: bold; margin: 0; padding: 0; text-decoration: underline; } .u436c1e03cd48d98dd0fcd00e59862316 .postTitle { color: #FFFFFF; font-size: 16px; font-weight: 600; margin: 0; padding: 0; width: 100%; } .u436c1e03cd48d98dd0fcd00e59862316 .ctaButton { background-color: #7F8C8D!important; color: #2980B9; border: none; border-radius: 3px; box-shadow: none; font-size: 14px; font-weight: bold; line-height: 26px; moz-border-radius: 3px; text-align: center; text-decoration: none; text-shadow: none; width: 80px; min-height: 80px; background: url(https://artscolumbia.org/wp-content/plugins/intelly-related-posts/assets/images/simple-arrow.png)no-repeat; position: absolute; right: 0; top: 0; } .u436c1e03cd48d98dd0fcd00e59862316:hover .ctaButton { background-color: #34495E!important; } .u436c1e03cd48d98dd0fcd00e59862316 .centered-text { display: table; height: 80px; padding-left : 18px; top: 0; } .u436c1e03cd48d98dd0fcd00e59862316 .u436c1e03cd48d98dd0fcd00e59862316-content { display: table-cell; margin: 0; padding: 0; padding-right: 108px; position: relative; vertical-align: middle; width: 100%; } .u436c1e03cd48d98dd0fcd00e59862316:after { content: ""; display: block; clear: both; } READ: Select describe and explain the religious rituals EssayThe position vector is drawn from the selected origin of your CSS to the objects location. Thus your new position vector is the sum of the original position vector plus the displacement vector. For the 3 legs of the given trip we would have: 01-3 = or O Del (where or O by our CSS choice). RL e Danna 0 DB. Combining these we then have: or O Del O DO 0 DO . Since the original position as zero, the final position is identical to the net displacement. 3) Two helicopters take off from the same landing area. One proceeds 10 km at 500 south of west. The second flies 8 km in the direction 650 south of east.